Consider three different raster systems with resolutions of 640 x 480, 1280 x 1024, and 2560 x 2048.

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a) What size is frame buffer (in bytes) for each of these systems to store 12 bits per pixel?

Because eight bits constitute a byte, frame-buffer sizes of the systems are as follows:                                     640 x 480 x 12 bits / 8 = 450KB;

1280 x 1024 x 12 bits / 8 = 1920KB;

2560 x 2048 x 12 bits / 8 = 7680KB;

b) How much storage (in bytes) is required for each system if 24 bits per pixel are to be stored?

Similarly, each of the above results is just doubled for 24 (12×2) bits of storage per pixel.

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Bijay Satyal
Oct 22, 2021
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