Evaluate the following expression Assume,
int i = 10, b=20,c=5,e=2; float q =2.5, d=4.5;
- a/b + (a/(2*b))
- f = ++a + b-- / q find value of f, a, and b
- G = b%a++; find value of G and a
- H = b%++a; find value of H and a
- a+2 < b || !c && a==d || a-2 <=e
i) a/b + (a/(2*b))
10/20 + ( 10/(2*20)) // substituite values of variables
10/20 + (10/40) // inner most parentheses is having highest precedence
10/20 + 0 //parentheses is having highest precedence so evaluate it
//first, 10/40(int/int) so result is 0
0 + 0 // division operators has higher precdence than +,
//10/20(int/int) so result is 0
0 // overall result of expression
ii) f = ++a + b-- / q find value of f, a, and b
f = ++10 + 20-- / 2.5 // substiuite values
f = ++10 + 20 / 2.5 // b =19, since postdecrement(--) operator has
//higher precedence evaluate it first according to steps
f = 11 + 20 / 2.5 // a = 11, since preincrement(++) operator has
//higher precedence evaluate it first according to steps
f = 11 + 8.0 // 20/2.5(int/float) so result is floating point
//value(implicit type conversion)
f = 19.0 // 11+8.0(int + float) so final result is also float
Therefore, f=19.0, a=11, b=19
iii) G = b%a++; find value of G and a
G = 20%10++; // substituite values
G = 20%10 // a=11, postincrement(++) has higher precedence so
// evaluate it first according to steps
G = 0 // % operator results remainder hence answer is 0
Therefore, G =0, a=11
iv) H = b%++a; find value of H and a
H = 20%++10; // substituite values
H = 20%11 // a=11, preincrement(++) has higher precedence so
// evaluate it first according to steps
H = 9 // % operator results remainder hence answer is 9
Therefore, H = 9, a = 11
v) a+2 < b || !c && a==d || a-2 <=e
10 + 2 < 20 || !5 && 10 == 4.5 || 10-2 <= 2 //substituite values
/* Since unary ! operator is having highest precedence so !5 => !true => false(0)
10 + 2 < 20 || 0 && 10 == 4.5 || 10-2 <= 2
/* + and – operator have higher precedence and both have same precedence, so use associativity rule i.e. left to right, hence + is evaluted first */
12 < 20 || 0 && 10==4.5 || 10-2 <= 2
/* - has higher precedence so evaluate it first,10-2 is 8 */
12<20 || 0 && 10 ==4.5 || 8 <=2
/* < and <= have higher precedence and both have same precedence, so use associativity rule i.e. left to right, hence evaluate < first, 12<20 is true so result is 1 */
1|| 0 && 10==4.5 || 8<=2
/* <= has higher precedence so evaluate it first, 8<=2 is false so result is 0 */
1 || 0 && 10==4.5 || 0
/*== has higher precedence so evaluate it first,10==4.5 is false, so result is 0*/
1 || 0 && 0 || 0
/* && has higher precedence so evaluate it first, 0&&0 is 0 */
1 || 0 || 0
// use associativity rule of || operator i.e. left to right and evaluate 1||0 is 1 */
1||0
1 // result of complete expression
